A) 25
C) 29
D) 11
Let x = the smallest (odd) integer. The next consecutive odd integer is x + 2, and the two consecutive odd integers after that are x + 4 and x + 6. We can create the equation:
(x + x + 2 + x + 4 + x + 6)/4 = 24
4x + 12 = 96
4x = 84
x = 21, so the largest integer is 27.
Related MCQs:
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