The sum of four consecutive two-digit odd numbers, when divided by 10, becomes a perfect square. Which of the following can possibly be one of these four numbers?

A) 21

B) 25

C) 41

D) 67

let sequence=x, x+2, x+4, x+6
sum of sequence=4x+12
if 4x+12 is a multiple of 10,
then x must have a units digit of 7
4*17+12=80; 80/10=8 no
4*27+12=120; 120/10=12 no
4*37+12=160; 160/10=16 yes
sequence=37, 39, 41, 43

 

Related MCQs:
  1. The average of four consecutive odd numbers is 24. Find the largest number:
  2. Find the sum of two consecutive even numbers, their difference of whose square is 84?
  3. If the highest four-digit number is subtracted from the lowest five-digit, what will be the resultant figure?
  4. Two numbers whose sum is 67 and difference is 3, the numbers are: