A) 6 days
B) 10 days
C) 15 days
D) 20 days
One day’s work of x = 1/20
One day’s work of y = 1/12
So work done by x in first 4 days
= 1/20×4= 1/5
So the remaining work be
1-1/5=4/5
now work done by x and y together = 1/20 + 1/12
=2/15
So the remaining work be done by both x and y
= 2/15 ×Days = 4/5
So D = 4/5×15/2 =3×2 = 6
Therefore for 6 days they worked till last.
Related MCQs:
- If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work?
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