Solve: a – b = 3, a2 +b2 = 29 then ab=?

A) 5

B) 10

C) 15

D) 20

a2+b2 = 29 ………..(1)

a-b = 3

(a-b) 2 = 9 ……..(2)

a2–2ab+b2=9, or

a2+b2 -2ab = 9

29–2ab = 9

2ab = 29–9 = 20

so ab = 20/2 = 10