If x + Y = 6, y + z = 7, and z + x = 9, the average (arithmetic mean) of x, y and z is?

A) 11/3

B) 11/2

C) 22/3

D) 11

x+y =6 …. ( i )
y+z =7 …. ( ii )
x+z =9 …. ( iii ) 
Adding ( i ) , ( ii ) and ( iii ) 
2x+2y+2z=22

Factor out 2

2x+2y+2z=22

2(x+y+z)=22

 (x+y+z)=11

Now taking Average 

 (x+y+z)/3 = 11/3