A is two years older than B who is twice as old as C. If the sum of the ages of A, B, and C is 27, how old is B?

A) 9

B) 10

C) 11

D) 12

Let the age of C be x.

Therefore, the age of B would be 2x.

And the age of A would be (2x + 2)

x + 2x + (2x + 2) = 27

5x + 2 = 27

5x = 27–2

5x = 25

x = 25/5

x = 5

Therefore, age of B = 2x = 2*5 = 10

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