A) 35
C) 45
D) 50
Let 1 man’s 1 day work = x and 1 woman’s 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
10 woman’s 1 day work = (1/400 x 10) = 1/40.
Hence, 10 women will complete the work in 40 days.
Related MCQs:
- Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will it take to complete the remaining work?
- Twelve men take 6 hours to finish a piece of work. After the 12 men have worked for 1 hour, the contractor decides to call in 8 more men. How many more hours would 20 men take to complete the remaining work?
- X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone, and then after 4 days, Y joined him until the completion of the work. How long did the work last?
- If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work?