A) 47

B) 49

C) 51

D) None of these

## 2567 ÷ 17 x 3 = ? + 180

A) 73

B) 271

C) 273

D) None of these

Let  ? = X

(2567/17) × 3 = X + 180

151 × 3 = X + 180

453 = X + 180

X = 453 – 180

X = 273

A) 11m – 5n

B) 11n – 11m

C) 11m – 7n

D) None of these

A) 0

B) 1

C) 2

D) None of these

## Solve:

If x/y = 1/3, then x2+y2/x2-y2  =?

A) 910

B) 5/4

C) 1

D) None of these

## If a/3= b/4= c/7 then (a+b+c)/c= ?

A) 1/7

B) 1/2

C) 2

D) None of these

We can write:

a/c = 3/7 and b/c = 4/7

(a+b+c)/c = a/c + b/c +1 = 3/7 + 4/7 +1 = 2

## A farmer divides his herd of cows among his four sons so that first son gets one half of the herd, the second son one-fourth, the third son one fifth and the fourth son 7 cows. the total number of cows in the herd is?

A) 100

B) 140

C) 180

D) None of these

Given total number of cows = X
Now, 1st son share = X/2
2nd son share = X/4
3rd son share = X/5
4th son share = 7

(X/2) + (X/4) + (X/5) + 7 = k

(20k-19X/20 = 7
=> X = 140

## I paid 3/5 of a bill. If Rs. 400 of the bill is still due. what was the total amount of the bill?

A) Rs 1000

B) Rs 1200

C) Rs. 1500

D) None of these

Paid= 3/5

Remaining = 1 – 3/5 = 2/5

Given condiotion:

2/5 x Total amount = 400

⇒       Total amount = 1000

## A man has in all Rs. 640 in the denominations of one-rupee, five rupeee and ten rupee notes. the number of each type of notes are equal. What is the total member of notes he has?

A) 90

B) 100

C) 120

D) None of these

Let number of notes of each denomination be x

Then:

x + 5x + 10x = 640

⇒ 16x = 640

∴ x = 40

Hence, total number of notes = 3x =3(4) = 120

## Ali went to a shop to buy 50 kg of rice. He buys two varieties of rice which cost him Rs. 4.5 per kg and Rs.5 per kg. He appends a total of Rs. 240. What was the quality of cheaper rice bought by him?

A) 20 kg

B) 25 kg

C) 30 kg

D) None of these

Let A be the amount of type of first rice and
B be the Amount of second type of rice

According to question:  A + B = 50 Kg
Also
A  x 4.5 + B x 5 = 240 Rs
Thus solving the above two equations
(50 – B) x 4.5 + 5B = 240
225 – 4.5 B + 5B = 240
0.5 B = 15
B = 15/ 0.5
B = 30 Kg
Thus A = 50 – 30 = 20 Kg