A farmer divides his herd of cows among his four sons so that first son gets one half of the herd, the second son one-fourth, the third son one fifth and the fourth son 7 cows. the total number of cows in the herd is?

A) 100

B) 140

C) 180

D) None of these

Given total number of cows = X
Now, 1st son share = X/2
2nd son share = X/4
3rd son share = X/5
4th son share = 7

(X/2) + (X/4) + (X/5) + 7 = k

  (20k-19X/20 = 7
                => X = 140

Related MCQs:
  1. Four boys shared a certain amount of money.The first received 1/6 of it, the second 1/8, and the third got 1/2. If the fourth received 5, how much was the total money?
  2. A father is now three times as old as his son Five years back, he was four times as old as his son. The age of the son (in years) is:
  3. A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?
  4. Bachal is three times as old as his son today. Five years ago, he was four times as old as his son. How old is Bachal today?