There are two sections A and B of a class, consisting of 36 and 44 students respectively. If the average weight of section A is 40kg and that of section B is 35kg, find the average weight of the whole class?

A) 30 kg

B) 35 kg

C) 37.25 kg

D) 42.50 kg

Total weight of (36 + 44) Students,
= (36 × 40 + 44 × 35) kg
= 2980 kg
Therefore average weight of the whole class,
= <span id="MathJax-Element-1-Frame" class="MathJax" style="outline: none; box-sizing: border-box; margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; font-size: 14.157px; line-height: normal; font-family: inherit; vertical-align: baseline; display: inline; text-indent: 0px; text-align: inherit; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;" tabindex="0" role="presentation" data-mathml="298080“>2980/80 kg
Therefore average weight = 37.25 kg.

Average of ten positive numbers is x If each number is increased by 10%, then x:

A) Remains unchanged

B) May decrease

C) May increase

D) Is increased by 10%

Let 10 numbers be x1, x2, x3 ….. x10
According to question average of these 10 numbers is 10.

⇒ (x1 + x2 + x3 + …….. + x10)/10 = x

Now if each number is increased by 10%, then new average, say y,

y = (1.1 x1 + 1.1 x2 + 1.1 x3 + ……… + 1.1 x10)/10
⇒ y = 1.1 × ({x1 + x2 + x3 + …….. + x10}/10)
⇒ y= 1.1 x
⇒ y is 10% increased.

Given that 543 x 21 = 11403. Find the value of: 1140.3 ÷ 5.43

A) 210

B) 150

C) 120

D) 200

First take: 1140.3/5.43

Remove decimal: 11403/10 divided by 543/100

                              =11403/10 * 100/543

As we know given 11403 =543*21 put into above step

                               543*21/10 * 100/543

   By cutting

                         We get 210 answer