A) 24
B) 26
D) 45
Let the one’s digit =x
Ten’s digit =y
Number =10y+x
10y+x=3(x+y)
10y+x=3x+3y
7y=2x⇒1
10y+x+45=10x+y
9x−9y=45
x−y=5
x=5+y⇒2
Substitute 2 in 1
7y=2(5+y)
7y=10+2y
y=2
x=5+2=7
So, the no. is 27.
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