Imaginary Part of the multiplicative inverse of a number 6-5i is?

A) 5/61

B) 6/61

C) -5/61

D) None of these

Multiplicative inverse of 6-5i is 1/6-5i so,

= (1/6-5i) x (6+5i/6+5i)

= (6+5i)/ 6²- 5i²  ∴ (a² – b²) = (a-b)(a+b)

By sloving we get

= 6/61 + 5i/61

 

 

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